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Tuesday, December 14, 2010
Age Problem 6
This is a Algebra age word problem question that was asked by a anonymous guest which asked, "Bob is one third the age of his father. In 12 years he will be half the age of his father. How old is each now?"
Let Bob's father age be x and at present, Bob is 1/3(x). In 12 years time, father's age will be x + 12 and Bob will be 1/2(x+12). And also Bob age will be (x/3)+12 Therefore (x/3)+ 12 = x/2 + 6 Multiply LHS and RHS by 3 x + 36 = 3x/2 + 18 Multiply LHS and RHS by 2 2x +72 = 3x + 36 x = 36 So father's age is 36 and Bob is 1/3 x 36 = 12 Bob 12 Father 36
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ReplyDeleteLet Bob's father age be x and at present, Bob is 1/3(x).
ReplyDeleteIn 12 years time, father's age will be x + 12 and Bob will be 1/2(x+12).
And also Bob age will be (x/3)+12
Therefore (x/3)+ 12 = x/2 + 6
Multiply LHS and RHS by 3
x + 36 = 3x/2 + 18
Multiply LHS and RHS by 2
2x +72 = 3x + 36
x = 36
So father's age is 36 and Bob is 1/3 x 36 = 12
Bob 12
Father 36