In this Algebra time/distance problem, Bob leaves his house towards Springfield at 60 mi/hr. After 1 hour, Steve follows taking the same road in the same direction as Bob but at 90 mi/hr. How long until Steve catches up to Bob, and how far would they have gone at that point?
Time Distance Problem 6 Solution
Monday, July 14, 2008
Time Distance Problem 6
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Lets consider the time when they meet as t.
ReplyDeleteDistance between Bob and Steve when Steve started: 60 x 1 = 60 mi
So we can say: 60 mi + 60 mph x t hrs = 90 mph x t hrs
=> 30 t = 60
=> t = 2 hrs
Hence, Steve will take two hours to catch up with Bob. Also, by that time, they would've gone 180 miles from the starting point.